| SortedList: SetByIndex |
Replaces the value at a specific index in a SortedList object.
Public Sub SetByIndex( ByVal Index As Long, ByRef Value As Variant )
The index sequence is based on the sort sequence. When an element is added, it is inserted into SortedList in the correct sort order, and the indexing adjusts accordingly. When an element is removed, the indexing also adjusts accordingly. Therefore, the index of a specific key/value pair might change as elements are added or removed from the SortedList object.
| Exception | Condition |
|---|---|
| ArgumentOutOfRangeException | Index is outside the range of valid indexes for the SortedList object. |
The following code example shows how to replace the value of an existing element in a SortedList object.
Public Sub Main() Dim List As New SortedList List.Add 2, "two" List.Add 3, "three" List.Add 1, "one" List.Add 0, "zero" List.Add 4, "four" Debug.Print "The SortedList contains the following values:" PrintIndexAndKeysAndValues List List.SetByIndex 3, "III" List.SetByIndex 4, "IV" Debug.Print "After replacing the value at index 3 and index 4," PrintIndexAndKeysAndValues List End Sub Private Sub PrintIndexAndKeysAndValues(ByVal List As SortedList) Dim i As Long Debug.Print t("\t-INDEX-\t-KEY-\t-VALUE-") For i = 0 To List.Count - 1 Debug.Print CorString.Format(t("\t[{0}]:\t{1}\t{2}"), i, List.GetKey(i), List.GetByIndex(i)) Next Debug.Print End Sub ' The following code produces the following output. ' ' The SortedList contains the following values: ' -INDEX- -KEY- -VALUE- ' [0]: 0 zero ' [1]: 1 one ' [2]: 2 two ' [3]: 3 three ' [4]: 4 four ' ' After replacing the value at index 3 and index 4, ' -INDEX- -KEY- -VALUE- ' [0]: 0 zero ' [1]: 1 one ' [2]: 2 two ' [3]: 3 III ' [4]: 4 IV